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Step-1

Title: Solve

Grade: 7-b Lesson: S1-L10

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 20/2 = 2(n - 3/2) + 8 \$
2	Canceling Numerator with \$2\$	\$ \cancel(20)^10/\cancel(2)^1 = 2(n - 3/2) + 8 \$
3	Taking LCM as '\$2\$'	\$ 10 = 2((2n - 3)/2) + 8 \$
4	After Simplification	\$ 10 = \cancel(2)((2n - 3)/\cancel(2)) + 8 \$ \$ 10 = 2n - 3 + 8 \$ \$ 2n - 3 + 8 = 10 \$
5	Move Constant terms to the right side	\$ 2n = 10 + 3 - 8 \$ \$ 2n = 5 \$
6	Dividing on both sides by '\$2\$' of the equality	\$ (\cancel(2^1)n)/\cancel(2)^1 = 5/2 \$
7	After Cancellation	\$ n = 5/2 \$
8	Answer	\$A = n = 5/2 \$

Steps

Problem

Solution

Solve

\$ 20/2 = 2(n - 3/2) + 8 \$

Canceling Numerator with \$2\$

\$ \cancel(20)^10/\cancel(2)^1 = 2(n - 3/2) + 8 \$

Taking LCM as '\$2\$'

\$ 10 = 2((2n - 3)/2) + 8 \$

After Simplification

\$ 10 = \cancel(2)((2n - 3)/\cancel(2)) + 8 \$

\$ 10 = 2n - 3 + 8 \$

\$ 2n - 3 + 8 = 10 \$

Move Constant terms to the right side

\$ 2n = 10 + 3 - 8 \$

\$ 2n = 5 \$

Dividing on both sides by '\$2\$' of the equality

\$ (\cancel(2^1)n)/\cancel(2)^1 = 5/2 \$

After Cancellation

\$ n = 5/2 \$

Answer

\$A = n = 5/2 \$