Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Find the value of x/y |
Grade: 7-a Lesson: S4-L7 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
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1 |
Problem |
Find the negative value of \$ x/y\$: |
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2 |
Hint |
Moving xy to left side |
\$ ((5x)^2 + (4y)^2) = -40(xy) \$ |
3 |
Step |
After simplification |
\$ (5x)^2 +40xy + (4y)^2 = 0 \$ |
4 |
Step |
Using identity \$a^2 + 2ab + b^2 = (a + b)^2\$ |
\$ (5x + 4y)^2 = 0 \$ |
5 |
Step |
Applying squareroot on both sides |
\$ \sqrt(5x + 4y)^2 = \sqrt0 \$ |
6 |
Step |
Cancelling Square & Squareroot |
\$ (5x + 4y) = 0 \$ |
7 |
Step |
Moving 4y to left side |
\$ (5x = -4y) \$ |
8 |
Step |
Transforming the above equation into \$ x/y \$ form |
\$ 5x = -4y \$ |
9 |
Step |
After simplification |
\$ 5x/y=-4 \$ |
10 |
Step |
After Transforming the above equation into \$ x/y \$ |
\$ x/y=-4/5 \$ |
11 |
Step |
The negative valve of \$ x/y \$ is |
\$ x/y=-4/5 \$ |
12 |
Answer |
D |
Tutor: Questions
Seq | Type | Question | Audio |
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1 |
Problem |
What did you learn from this problem? |
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2 |
Clue |
What did you learn from the clues? |
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3 |
Hint |
What did you learn from the Hints? |
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4 |
Step |
What did you learn from the Steps? |
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5 |
Step |
How can we improve the Steps? |
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