Step-2

Title: Solve the equation of the fractions

Grade: 7-a Lesson: S4-L6

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Given that:
\$ 4/(3x + 10) = 2/(x - 3) \$

2

Hint

Multiply both sides on (3x + 10)(x - 3)

\$ 4/\cancel((3x + 10)) \times \cancel((3x + 10))(x - 3) = 2/\cancel((x - 3)) \times (3x + 10)\cancel((x - 3)) \$

3

Step

After cancellation

\$ 4(x - 3) = 2(3x + 10) \$

4

Step

After multiplication

\$ 4x - 12 = 6x + 20 \$

5

Step

Add both sides on 12

\$ 4x - \cancel(12) + \cancel(12) = 6x + 20 + 12 \$

6

Step

After cancellation

\$4x = 6x + 32 \$

7

Step

Substract both sides on 6x

\$ 4x - 6x = \cancel(6x) - \cancel(6x) + 32 \$

8

Step

After cancellation

\$-2x = 32 \$

9

Step

Divide on both sides 2

\$ (-\cancel(2)x)/\cancel(2) = \cancel(32)^16/\cancel(2)^1 \$

10

Step

After cancellation

\$ x = -16 \$

11

Answer

B

Tutor: Questions

Seq Type Question Audio

1

Problem

What did you learn from this problem?

2

Clue

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3

Hint

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4

Step

What did you learn from the Steps?

5

Step

How can we improve the Steps?


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