1

Simplify

\$ (3/2)^-9 × (3/2)^10 +(3/2) \$

2

By using the formula \$(a/b)^-n = (b/a)^n\$

\$ (2/3)^9 × (3/2)^10 + 3/2 \$

3

Using law of exponent \$(a/b)^n = a^n/b^n\$ and

BODMAS rule

\$ \cancel(2^9)/\cancel(3^9) × \cancel(3^10)^1/\cancel(2^10)^1 + 3/2 \$

4

After cancellation we get

\$ 3/2 + 3/2 \$

5

Taking LCM as 2

\$ (3 + 3)/2 \$

6

After simplification we get

\$ \cancel6^3/\cancel2^1 \$

7

After cancellation we get

\$ 3 \$

8

Answer

A = \$ 3 \$