Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Absolute values |
Grade: 6-a Lesson: S1-L5 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
Simplify : |
|
2 |
Step |
Given the expression |
\$| 17 times 5 | \div | 4 - 19 | \$ |
3 |
Step |
First calculate the values inside the absolute values: |
|
4 |
Step |
The absolute value of any positive number is the number itself |
\$|17 times 5|\$ = \$|85|\$ = 85 |
5 |
Step |
The absolute value of any negative number is its positive counterpart |
\$|4-19|\$ = \$|-15|\$ = 15 |
6 |
Step |
Now, we substitute these values back into the original expression: |
\$85/15\$ |
7 |
Step |
The simplified expression is |
\$ 17/3\$ |
8 |
Choice.A |
This option is incorrect. The simplified expression is positive, not negative |
\$ - 17/3\$ |
9 |
Choice.B |
This option is incorrect. It does not represent the correct result of the simplification |
\$ 3/17\$ |
10 |
Choice.C |
This option is correct. After simplifying \$ \∣ 17 × 5 \∣ ÷ \∣ 4 − 19 \∣ \$, we get \$ 17/3 \$ |
\$17/3\$ |
11 |
Choice.D |
This option is incorrect. The simplification results in a positive fraction, not a negative one |
\$ -3/17\$ |
12 |
Answer |
Option |
C |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
|
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