Lesson: Step-5

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|1|{sbBox2-problem} 2+|Solve the following system of equations:
3x - 2y = 1 and 4x + y = 5. |2|Step: >|The given equation-1 is |3x - 2y = 1 |3|Step: >|The given equation-2 is |4x + y = 5 |4|{sbBox2-hint}|Multiply equation-2 by 2 we get equation-3 | 8x + 2y = 10 |5|Step: >|Add equation-3
and equation-1 | \$8x + \cancel(2y) = 10\$
\$3x - \cancel(2y) = 1\$ |6|Step:|After simplification, | 11x - 0 = 11 |7|Step:|Solve for x value | 11x = 11
x = 1 |8|{sbBox2-clue}|Substitute the x value in equation - 2, then we get y | 4 + y = 5
y = 1 |9|Step: 2+|Therefore, the x and y values are x = 1, y = 1 |10|{sbBox2-sumup} |Can you summarize what you’ve understood in the above steps? |audio::https://uat-media.saibook.org/edu/family/counselor/v3/common/lesson/steps/sumup.mp3[width=24px,,float="right"] |11|{sbBox2-choice-a} |This is not a valid solution to the system of equations because it does not satisfy the first equation| x = 2 and y = 1
|12|{sbBox2-choice-b} |This solution is valid for the system of equations as it satisfies both equations | x = 1 and y = 1
|13|{sbBox2-choice-c} |This is not a valid solution to the system of equations because it does not satisfy the first equation| x = 3 and y = 2
|14|{sbBox2-choice-d} |This is not a valid solution to the system of equations because it does not satisfy the first equation| x = 4 and y = 5
|15|{sbBox2-answer}| Option | B |16|{sbBox2-sumup} |Can you summarize what you’ve understood in the above steps? |audio::https://uat-media.saibook.org/edu/family/counselor/v3/common/lesson/steps/sumup.mp3[width=24px,,float="right"]

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