Lesson: Step-4

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|1|{sbBox2-problem} 2+|Solve the following system of equations:
3x + y = 2 and x - 2y = 1. |2|Step: >|The given equation-1 is |3x + y = 2 |3|Step: >|The given equation-2 is |x - 2y = 1 |4|{sbBox2-hint}|Multiply equation-1 by 2 we get equation-3| 6x + 2y = 4 |5|Step: >|Add equation-3
and equation-2 | \$6x + \cancel(2y) = 4\$
  \$ x - \cancel(2y) = 1\$ |6|Step:|After simplification, | 7x - 0 = 5 |7|Step:|Find for x value | 7x = 5
\$x = 5/7\$ |8|{sbBox2-clue}|Substitute the x value in equation - 2, then we get y | \$ 5/7 - 2y = 1 \$
\$y = - 1/7 \$ |9|Step: 2+|Therefore, the x and y values are \$x = 5/7, y = -1/7\$ |10|{sbBox2-sumup} |Can you summarize what you’ve understood in the above steps? |audio::https://uat-media.saibook.org/edu/family/counselor/v3/common/lesson/steps/sumup.mp3[width=24px,,float="right"] |11|{sbBox2-choice-a} | The solution cannot satisfy both system equations simultaneously and is therefore considered invalid | \$ x = 6/11\$ and \$ y = -1/7 \$
|12|{sbBox2-choice-b} | This solution satisfies both equations of the system at the same time and is considered valid | \$ x = 5/7\$ and \$ y = -1/7 \$ |13|{sbBox2-choice-c} |The solution cannot satisfy both system equations simultaneously and is therefore considered invalid | \$ x = 5/7\$ and \$ y = 1/7 \$
|14|{sbBox2-choice-d} | The solution cannot satisfy both system equations simultaneously and is therefore considered invalid | \$ x = -5/7\$ and \$ y = -1/7 \$
|15|{sbBox2-answer}| Option | B |16|{sbBox2-sumup} |Can you summarize what you’ve understood in the above steps? |audio::https://uat-media.saibook.org/edu/family/counselor/v3/common/lesson/steps/sumup.mp3[width=24px,,float="right"]

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