Lesson: Step-3

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|1|{sbBox2-problem} 2+|Solve the following system of equations:
5x - y = 11 and 3x + 2y = 4. |2|Step: >|The given equation-1 is |5x - y = 11 |3|Step: >|The given equation-2 is |3x + 2y = 4 |4|{sbBox2-hint}|Multiply equation-1 by 2 we get equation-3 | 10x - 2y = 22 |5|Step: >|Add the equation-3
and equation-1 | \$10x - \cancel(2y) = 22\$
  \$ 3x + \cancel(2y) = 4\$ |6|Step:|After simplification, | 13x + 0 = 26 |7|Step:|Finding the x value | 13x = 26
x = 2 |8|{sbBox2-clue}|Substitute the x value in equation-1, then we get y value | 10 - y = 11
y = - 1 |9|Step: 2+|Therefore, the x and y values are x = 2, y = -1 |10|{sbBox2-sumup} |Can you summarize what you’ve understood in the above steps? |audio::https://uat-media.saibook.org/edu/family/counselor/v3/common/lesson/steps/sumup.mp3[width=24px,,float="right"] |11|{sbBox2-choice-a} |The system of equations is unsatisfied with x = 2 and y = 0; valid values must satisfy both equations concurrently| x = 2, y = 0
|12|{sbBox2-choice-b} |The system of equations is unsatisfied with x = 5 and y = -1 ; valid values must satisfy both equations concurrently| x = 5 and y = -1 |13|{sbBox2-choice-c} |At x = 2 and y = -1 in this stage, check if these values satisfy both equations by substituting them into the original expressions| x = 2 and y = - 1
|14|{sbBox2-choice-d} |The system of equations is unsatisfied with x = -7 and y = 3; valid values must satisfy both equations concurrently| x = -7 and y = 3
|15|{sbBox2-answer}| Option | C |16|{sbBox2-sumup} |Can you summarize what you’ve understood in the above steps? |audio::https://uat-media.saibook.org/edu/family/counselor/v3/common/lesson/steps/sumup.mp3[width=24px,,float="right"]

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